Hi,
I have a simple routine that displays a form on the screen, and then
removes it after a second or two. I've noticed that the routine is
called twice... once after it has been removed from the timer.
void remove_form(int id, void *p)
{
FL_FORM *ob = (FL_FORM *)p;
puts("Removing");
if (fl_form_is_visible(ob))
fl_hide_form(ob);
}
results in...
Removing
Removing
In RemoveTimeout [timeout.c 69] ID 4 not found
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Orn Einar Hansen oe.hansen@oehansen.pp.se
oehansen@daimi.aau.dk
voice+fax; +46 035 217194
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